Poj Solution 1973

http://poj.org/problem?id=1973

#include<iostream>
using namespace std;
int f[110],ft[110];
int n,m;
int t1[110],t2[110];

bool checkout(int t)
{
    int i,j,a,b;
    for(i=1;i<=m;i++)
        f[i]=-1;
    f[0]=0;

    for(j=0;j<=m;j++)
        ft[j]=f[j];

    for(i=0;i<n;i++)
    {
        for(a=0;a<=t/t1[i]&&a<=m;a++)
        {
            b=(t-t1[i]*a)/t2[i];
            for(j=0;j<=m-a;j++)
                if(f[j]>=0)
                {
                    if(ft[j+a]<f[j]+b)
                        ft[j+a]=f[j]+b;
                }
        }
        for(j=0;j<=m;j++)
          f[j]=ft[j];
        if(f[m]>=m)return 1;
    }
    return f[m]>=m;
}

int main()
{
    int t,a,b,i,c;
    cin>>t;
    while(t--)
    {
        cin>>n>>m;
        for(i=0;i<n;i++)
            cin>>t1[i]>>t2[i];
        a=0;
        b=9999;
        while(a<b)
        {
            c=(a+b)/2;
            if(checkout(c))b=c;
            else a=c+1;
        }
        cout<<b<<endl;
    }
    return 0;
}
											
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